At the school, Storey T and Storey U had an equal number of desks at first. If 8 desks were removed from Storey U and 6 times as many desks were removed from Storey T as Storey U, the number of desks in Storey U would be 5 times as many as in Storey T. Find the number of desks on each storey.
| |
Storey T |
Storey U |
| Before |
1 u |
1 u |
| Change |
- 48 |
- 8 |
| After |
1 u - 48 |
1 u - 8 |
Number of desks removed from Storey T
= 6 x 8
= 48
Number of desks on Storey T and Storey U at first is the same.
Number of desks on Storey U is 5 times as many as Storey T in the end. If the number of desks on Storey T increases by 5 times, the number of desks on Storey T and Storey U will be the same.
5(1 u - 48) = 1 u - 8
5 u - 240 = 1 u - 8
5 u - 1 u = 240 - 8
4 u = 232
1 u = 232 ÷ 4 = 58
Number of desks in each floor
= 1 u
= 58
Answer(s): 58
