At the school, Level F and Level G had an equal number of tables at first. If 8 tables were removed from Level G and 6 times as many tables were removed from Level F as Level G, the number of tables in Level G would be 5 times as many as in Level F. Find the number of tables on each level.
| |
Level F |
Level G |
| Before |
1 u |
1 u |
| Change |
- 48 |
- 8 |
| After |
1 u - 48 |
1 u - 8 |
Number of tables removed from Level F
= 6 x 8
= 48
Number of tables on Level F and Level G at first is the same.
Number of tables on Level G is 5 times as many as Level F in the end. If the number of tables on Level F increases by 5 times, the number of tables on Level F and Level G will be the same.
5(1 u - 48) = 1 u - 8
5 u - 240 = 1 u - 8
5 u - 1 u = 240 - 8
4 u = 232
1 u = 232 ÷ 4 = 58
Number of tables in each floor
= 1 u
= 58
Answer(s): 58
