At the school, Floor M and Floor N had an equal number of chairs at first. If 8 chairs were removed from Floor N and 4 times as many chairs were removed from Floor M as Floor N, the number of chairs in Floor N would be 4 times as many as in Floor M. Find the number of chairs on each floor.

	Floor M	Floor N
Before	1 u	1 u
Change	- 32	- 8
After	1 u - 32	1 u - 8

Number of chairs removed from Floor M
= 4 x 8
= 32

Number of chairs on Floor M and Floor N at first is the same.

Number of chairs on Floor N is 4 times as many as Floor M in the end. If the number of chairs on Floor M increases by 4 times, the number of chairs on Floor M and Floor N will be the same.

4(1 u - 32) = 1 u - 8
4 u - 128 = 1 u - 8 
4 u - 1 u = 128 - 8
3 u = 120

1 u = 120 ÷ 3 = 40

Number of chairs in each floor
= 1 u
= 40

Answer(s): 40