At the office building, Floor S and Floor T had an equal number of tables at first. If 6 tables were removed from Floor T and 7 times as many tables were removed from Floor S as Floor T, the number of tables in Floor T would be 3 times as many as in Floor S. Find the number of tables on each floor.
| |
Floor S |
Floor T |
| Before |
1 u + 42 |
3 u + 6 |
| Change |
- 42 |
- 6 |
| After |
1 u |
3 u |
Number of tables removed from Floor S
= 7 x 6
= 42
Number of tables on Floor S and Floor T at first is the same.
3 u + 6 = 1 u + 42
3 u - 1 u = 42 - 6
2 u = 36
1 u = 36 ÷ 2 = 18
Number of tables on each floor
= 1 u + 42
= 18 + 42
= 60
Answer(s): 60
