At the school, Level K and Level L had an equal number of chairs at first. If 9 chairs were removed from Level L and 3 times as many chairs were removed from Level K as Level L, the number of chairs in Level L would be 4 times as many as in Level K. Find the number of chairs on each level.
| |
Level K |
Level L |
| Before |
1 u + 27 |
4 u + 9 |
| Change |
- 27 |
- 9 |
| After |
1 u |
4 u |
Number of chairs removed from Level K
= 3 x 9
= 27
Number of chairs on Level K and Level L at first is the same.
4 u + 9 = 1 u + 27
4 u - 1 u = 27 - 9
3 u = 18
1 u = 18 ÷ 3 = 6
Number of chairs on each level
= 1 u + 27
= 6 + 27
= 33
Answer(s): 33
