At the hospital, Storey K and Storey L had an equal number of beds at first. If 7 beds were removed from Storey L and 7 times as many beds were removed from Storey K as Storey L, the number of beds in Storey L would be 4 times as many as in Storey K. Find the number of beds on each storey.
|
Storey K |
Storey L |
Before |
1 u |
1 u |
Change |
- 49 |
- 7 |
After |
1 u - 49 |
1 u - 7 |
Number of beds removed from Storey K
= 7 x 7
= 49
Number of beds on Storey K and Storey L at first is the same.
Number of beds on Storey L is 4 times as many as Storey K in the end. If the number of beds on Storey K increases by 4 times, the number of beds on Storey K and Storey L will be the same.
4(1 u - 49) = 1 u - 7
4 u - 196 = 1 u - 7
4 u - 1 u = 196 - 7
3 u = 189
1 u = 189 ÷ 3 = 63
Number of beds in each floor
= 1 u
= 63
Answer(s): 63