At the office building, Storey C and Storey D had an equal number of chairs at first. If 8 chairs were removed from Storey D and 5 times as many chairs were removed from Storey C as Storey D, the number of chairs in Storey D would be 3 times as many as in Storey C. Find the number of chairs on each storey.
|
Storey C |
Storey D |
Before |
1 u + 40 |
3 u + 8 |
Change |
- 40 |
- 8 |
After |
1 u |
3 u |
Number of chairs removed from Storey C
= 5 x 8
= 40
Number of chairs on Storey C and Storey D at first is the same.
3 u + 8 = 1 u + 40
3 u - 1 u = 40 - 8
2 u = 32
1 u = 32 ÷ 2 = 16
Number of chairs on each storey
= 1 u + 40
= 16 + 40
= 56
Answer(s): 56