At the hospital, Floor A and Floor B had an equal number of beds at first. If 6 beds were removed from Floor B and 6 times as many beds were removed from Floor A as Floor B, the number of beds in Floor B would be 3 times as many as in Floor A. Find the number of beds on each floor.
| |
Floor A |
Floor B |
| Before |
1 u + 36 |
3 u + 6 |
| Change |
- 36 |
- 6 |
| After |
1 u |
3 u |
Number of beds removed from Floor A
= 6 x 6
= 36
Number of beds on Floor A and Floor B at first is the same.
3 u + 6 = 1 u + 36
3 u - 1 u = 36 - 6
2 u = 30
1 u = 30 ÷ 2 = 15
Number of beds on each floor
= 1 u + 36
= 15 + 36
= 51
Answer(s): 51
