At the office building, Floor C and Floor D had an equal number of tables at first. If 6 tables were removed from Floor D and 6 times as many tables were removed from Floor C as Floor D, the number of tables in Floor D would be 3 times as many as in Floor C. Find the number of tables on each floor.
| |
Floor C |
Floor D |
| Before |
1 u + 36 |
3 u + 6 |
| Change |
- 36 |
- 6 |
| After |
1 u |
3 u |
Number of tables removed from Floor C
= 6 x 6
= 36
Number of tables on Floor C and Floor D at first is the same.
3 u + 6 = 1 u + 36
3 u - 1 u = 36 - 6
2 u = 30
1 u = 30 ÷ 2 = 15
Number of tables on each floor
= 1 u + 36
= 15 + 36
= 51
Answer(s): 51
