At the hospital, Floor V and Floor W had an equal number of beds at first. If 8 beds were removed from Floor W and 7 times as many beds were removed from Floor V as Floor W, the number of beds in Floor W would be 3 times as many as in Floor V. Find the number of beds on each floor.
|
Floor V |
Floor W |
Before |
1 u |
1 u |
Change |
- 56 |
- 8 |
After |
1 u - 56 |
1 u - 8 |
Number of beds removed from Floor V
= 7 x 8
= 56
Number of beds on Floor V and Floor W at first is the same.
Number of beds on Floor W is 3 times as many as Floor V in the end. If the number of beds on Floor V increases by 3 times, the number of beds on Floor V and Floor W will be the same.
3(1 u - 56) = 1 u - 8
3 u - 168 = 1 u - 8
3 u - 1 u = 168 - 8
2 u = 160
1 u = 160 ÷ 2 = 80
Number of beds in each floor
= 1 u
= 80
Answer(s): 80