At the school, Level E and Level F had an equal number of desks at first. If 7 desks were removed from Level F and 5 times as many desks were removed from Level E as Level F, the number of desks in Level F would be 3 times as many as in Level E. Find the number of desks on each level.
|
Level E |
Level F |
Before |
1 u |
1 u |
Change |
- 35 |
- 7 |
After |
1 u - 35 |
1 u - 7 |
Number of desks removed from Level E
= 5 x 7
= 35
Number of desks on Level E and Level F at first is the same.
Number of desks on Level F is 3 times as many as Level E in the end. If the number of desks on Level E increases by 3 times, the number of desks on Level E and Level F will be the same.
3(1 u - 35) = 1 u - 7
3 u - 105 = 1 u - 7
3 u - 1 u = 105 - 7
2 u = 98
1 u = 98 ÷ 2 = 49
Number of desks in each floor
= 1 u
= 49
Answer(s): 49