At the school, Floor T and Floor U had an equal number of desks at first. If 6 desks were removed from Floor U and 5 times as many desks were removed from Floor T as Floor U, the number of desks in Floor U would be 5 times as many as in Floor T. Find the number of desks on each floor.
| |
Floor T |
Floor U |
| Before |
1 u + 30 |
5 u + 6 |
| Change |
- 30 |
- 6 |
| After |
1 u |
5 u |
Number of desks removed from Floor T
= 5 x 6
= 30
Number of desks on Floor T and Floor U at first is the same.
5 u + 6 = 1 u + 30
5 u - 1 u = 30 - 6
4 u = 24
1 u = 24 ÷ 4 = 6
Number of desks on each floor
= 1 u + 30
= 6 + 30
= 36
Answer(s): 36
