At the office building, Floor A and Floor B had an equal number of tables at first. If 7 tables were removed from Floor B and 5 times as many tables were removed from Floor A as Floor B, the number of tables in Floor B would be 5 times as many as in Floor A. Find the number of tables on each floor.
| |
Floor A |
Floor B |
| Before |
1 u + 35 |
5 u + 7 |
| Change |
- 35 |
- 7 |
| After |
1 u |
5 u |
Number of tables removed from Floor A
= 5 x 7
= 35
Number of tables on Floor A and Floor B at first is the same.
5 u + 7 = 1 u + 35
5 u - 1 u = 35 - 7
4 u = 28
1 u = 28 ÷ 4 = 7
Number of tables on each floor
= 1 u + 35
= 7 + 35
= 42
Answer(s): 42
