At the hospital, Floor G and Floor H had an equal number of beds at first. If 6 beds were removed from Floor H and 3 times as many beds were removed from Floor G as Floor H, the number of beds in Floor H would be 4 times as many as in Floor G. Find the number of beds on each floor.
| |
Floor G |
Floor H |
| Before |
1 u + 18 |
4 u + 6 |
| Change |
- 18 |
- 6 |
| After |
1 u |
4 u |
Number of beds removed from Floor G
= 3 x 6
= 18
Number of beds on Floor G and Floor H at first is the same.
4 u + 6 = 1 u + 18
4 u - 1 u = 18 - 6
3 u = 12
1 u = 12 ÷ 3 = 4
Number of beds on each floor
= 1 u + 18
= 4 + 18
= 22
Answer(s): 22
