At the school, Level B and Level C had an equal number of chairs at first. If 6 chairs were removed from Level C and 6 times as many chairs were removed from Level B as Level C, the number of chairs in Level C would be 4 times as many as in Level B. Find the number of chairs on each level.
| |
Level B |
Level C |
| Before |
1 u + 36 |
4 u + 6 |
| Change |
- 36 |
- 6 |
| After |
1 u |
4 u |
Number of chairs removed from Level B
= 6 x 6
= 36
Number of chairs on Level B and Level C at first is the same.
4 u + 6 = 1 u + 36
4 u - 1 u = 36 - 6
3 u = 30
1 u = 30 ÷ 3 = 10
Number of chairs on each level
= 1 u + 36
= 10 + 36
= 46
Answer(s): 46
