At the hospital, Level F and Level G had an equal number of beds at first. If 9 beds were removed from Level G and 3 times as many beds were removed from Level F as Level G, the number of beds in Level G would be 3 times as many as in Level F. Find the number of beds on each level.
| |
Level F |
Level G |
| Before |
1 u + 27 |
3 u + 9 |
| Change |
- 27 |
- 9 |
| After |
1 u |
3 u |
Number of beds removed from Level F
= 3 x 9
= 27
Number of beds on Level F and Level G at first is the same.
3 u + 9 = 1 u + 27
3 u - 1 u = 27 - 9
2 u = 18
1 u = 18 ÷ 2 = 9
Number of beds on each level
= 1 u + 27
= 9 + 27
= 36
Answer(s): 36
