At the school, Level G and Level H had an equal number of chairs at first. If 8 chairs were removed from Level H and 6 times as many chairs were removed from Level G as Level H, the number of chairs in Level H would be 5 times as many as in Level G. Find the number of chairs on each level.
| |
Level G |
Level H |
| Before |
1 u |
1 u |
| Change |
- 48 |
- 8 |
| After |
1 u - 48 |
1 u - 8 |
Number of chairs removed from Level G
= 6 x 8
= 48
Number of chairs on Level G and Level H at first is the same.
Number of chairs on Level H is 5 times as many as Level G in the end. If the number of chairs on Level G increases by 5 times, the number of chairs on Level G and Level H will be the same.
5(1 u - 48) = 1 u - 8
5 u - 240 = 1 u - 8
5 u - 1 u = 240 - 8
4 u = 232
1 u = 232 ÷ 4 = 58
Number of chairs in each floor
= 1 u
= 58
Answer(s): 58
