At the hospital, Floor Q and Floor R had an equal number of beds at first. If 9 beds were removed from Floor R and 7 times as many beds were removed from Floor Q as Floor R, the number of beds in Floor R would be 3 times as many as in Floor Q. Find the number of beds on each floor.
| |
Floor Q |
Floor R |
| Before |
1 u |
1 u |
| Change |
- 63 |
- 9 |
| After |
1 u - 63 |
1 u - 9 |
Number of beds removed from Floor Q
= 7 x 9
= 63
Number of beds on Floor Q and Floor R at first is the same.
Number of beds on Floor R is 3 times as many as Floor Q in the end. If the number of beds on Floor Q increases by 3 times, the number of beds on Floor Q and Floor R will be the same.
3(1 u - 63) = 1 u - 9
3 u - 189 = 1 u - 9
3 u - 1 u = 189 - 9
2 u = 180
1 u = 180 ÷ 2 = 90
Number of beds in each floor
= 1 u
= 90
Answer(s): 90
