At the school, Level D and Level E had an equal number of desks at first. If 7 desks were removed from Level E and 7 times as many desks were removed from Level D as Level E, the number of desks in Level E would be 3 times as many as in Level D. Find the number of desks on each level.
| |
Level D |
Level E |
| Before |
1 u + 49 |
3 u + 7 |
| Change |
- 49 |
- 7 |
| After |
1 u |
3 u |
Number of desks removed from Level D
= 7 x 7
= 49
Number of desks on Level D and Level E at first is the same.
3 u + 7 = 1 u + 49
3 u - 1 u = 49 - 7
2 u = 42
1 u = 42 ÷ 2 = 21
Number of desks on each level
= 1 u + 49
= 21 + 49
= 70
Answer(s): 70
