At the hospital, Level J and Level K had an equal number of beds at first. If 6 beds were removed from Level K and 3 times as many beds were removed from Level J as Level K, the number of beds in Level K would be 4 times as many as in Level J. Find the number of beds on each level.
| |
Level J |
Level K |
| Before |
1 u + 18 |
4 u + 6 |
| Change |
- 18 |
- 6 |
| After |
1 u |
4 u |
Number of beds removed from Level J
= 3 x 6
= 18
Number of beds on Level J and Level K at first is the same.
4 u + 6 = 1 u + 18
4 u - 1 u = 18 - 6
3 u = 12
1 u = 12 ÷ 3 = 4
Number of beds on each level
= 1 u + 18
= 4 + 18
= 22
Answer(s): 22
