At the office building, Storey Y and Storey Z had an equal number of chairs at first. If 8 chairs were removed from Storey Z and 4 times as many chairs were removed from Storey Y as Storey Z, the number of chairs in Storey Z would be 4 times as many as in Storey Y. Find the number of chairs on each storey.
| |
Storey Y |
Storey Z |
| Before |
1 u + 32 |
4 u + 8 |
| Change |
- 32 |
- 8 |
| After |
1 u |
4 u |
Number of chairs removed from Storey Y
= 4 x 8
= 32
Number of chairs on Storey Y and Storey Z at first is the same.
4 u + 8 = 1 u + 32
4 u - 1 u = 32 - 8
3 u = 24
1 u = 24 ÷ 3 = 8
Number of chairs on each storey
= 1 u + 32
= 8 + 32
= 40
Answer(s): 40
