The number of green kiwis is the same as the number of golden apples in a bag. After removing
18 of the kiwis, there were 29 green kiwis and 153 golden apples left in the bag. Then, another 52 green kiwis and 52 golden apples were removed and there were
38 of the kiwis left in the end. How many green kiwis were removed altogether?
| |
Green Kiwis |
Golden Apples |
Total |
| Before |
1 p
104 |
1 p
104 |
8 u |
| Change 1 |
- ? (18 of the total) |
- 5 u |
| After 1 |
29 |
153 |
| Change 2 |
- 52 |
- 52 |
| After 2 |
78 |
3 u |
Number of kiwis left
= 29 + 153 - 52 - 52
= 78
3 u = 78
1 u = 78 ÷ 3 = 26
Total number of kiwis at first
= 8 u
= 8 x 26
= 208
Number of green kiwis at first
= 208 ÷ 2
= 104
Number of green kiwis removed at first
= 104 - 29
= 75
Total number of green kiwis removed
= 75 + 52
= 127
Answer(s): 127
