The number of green kiwis is the same as the number of golden apples in a bag. After removing
15 of the kiwis, there were 23 green kiwis and 157 golden apples left in the bag. Then, another 40 green kiwis and 40 golden apples were removed and there were
49 of the kiwis left in the end. How many green kiwis were removed altogether?
|
Green Kiwis |
Golden Apples |
Total |
Before |
1 p 112.5 |
1 p 112.5 |
9 u |
Change 1 |
- ? (15 of the total) |
- 5 u |
After 1 |
23 |
157 |
Change 2 |
- 40 |
- 40 |
After 2 |
100 |
4 u |
Number of kiwis left
= 23 + 157 - 40 - 40
= 100
4 u = 100
1 u = 100 ÷ 4 = 25
Total number of kiwis at first
= 9 u
= 9 x 25
= 225
Number of green kiwis at first
= 225 ÷ 2
= 112.5
Number of green kiwis removed at first
= 112.5 - 23
= 89.5
Total number of green kiwis removed
= 89.5 + 40
= 129.5
Answer(s): 129.5