The number of golden apples is the same as the number of green apples in a bag. After removing
15 of the kiwis, there were 28 golden apples and 180 green apples left in the bag. Then, another 65 golden apples and 65 green apples were removed and there were
310 of the kiwis left in the end. How many golden apples were removed altogether?
|
Golden Apples |
Green Apples |
Total |
Before |
1 p 130 |
1 p 130 |
10 u |
Change 1 |
- ? (15 of the total) |
- 7 u |
After 1 |
28 |
180 |
Change 2 |
- 65 |
- 65 |
After 2 |
78 |
3 u |
Number of kiwis left
= 28 + 180 - 65 - 65
= 78
3 u = 78
1 u = 78 ÷ 3 = 26
Total number of kiwis at first
= 10 u
= 10 x 26
= 260
Number of golden apples at first
= 260 ÷ 2
= 130
Number of golden apples removed at first
= 130 - 28
= 102
Total number of golden apples removed
= 102 + 65
= 167
Answer(s): 167