The number of red grapes is the same as the number of green grapes in a bag. After removing
14 of the grapes, there were 26 red grapes and 94 green grapes left in the bag. Then, another 36 red grapes and 36 green grapes were removed and there were
310 of the grapes left in the end. How many red grapes were removed altogether?
| |
Red Grapes |
Green Grapes |
Total |
| Before |
1 p
80 |
1 p
80 |
10 u |
| Change 1 |
- ? (14 of the total) |
- 7 u |
| After 1 |
26 |
94 |
| Change 2 |
- 36 |
- 36 |
| After 2 |
48 |
3 u |
Number of grapes left
= 26 + 94 - 36 - 36
= 48
3 u = 48
1 u = 48 ÷ 3 = 16
Total number of grapes at first
= 10 u
= 10 x 16
= 160
Number of red grapes at first
= 160 ÷ 2
= 80
Number of red grapes removed at first
= 80 - 26
= 54
Total number of red grapes removed
= 54 + 36
= 90
Answer(s): 90
