The number of golden apples is the same as the number of green apples in a bag. After removing
25 of the kiwis, there were 48 golden apples and 24 green apples left in the bag. Then, another 11 golden apples and 11 green apples were removed and there were
512 of the kiwis left in the end. How many golden apples were removed altogether?
| |
Golden Apples |
Green Apples |
Total |
| Before |
1 p
60 |
1 p
60 |
12 u |
| Change 1 |
- ? (25 of the total) |
- 7 u |
| After 1 |
48 |
24 |
| Change 2 |
- 11 |
- 11 |
| After 2 |
50 |
5 u |
Number of kiwis left
= 48 + 24 - 11 - 11
= 50
5 u = 50
1 u = 50 ÷ 5 = 10
Total number of kiwis at first
= 12 u
= 12 x 10
= 120
Number of golden apples at first
= 120 ÷ 2
= 60
Number of golden apples removed at first
= 60 - 48
= 12
Total number of golden apples removed
= 12 + 11
= 23
Answer(s): 23
