The number of green apples is the same as the number of red apples in a bag. After removing
14 of the apples, there were 48 green apples and 72 red apples left in the bag. Then, another 36 green apples and 36 red apples were removed and there were
310 of the apples left in the end. How many green apples were removed altogether?
| |
Green Apples |
Red Apples |
Total |
| Before |
1 p
80 |
1 p
80 |
10 u |
| Change 1 |
- ? (14 of the total) |
- 7 u |
| After 1 |
48 |
72 |
| Change 2 |
- 36 |
- 36 |
| After 2 |
48 |
3 u |
Number of apples left
= 48 + 72 - 36 - 36
= 48
3 u = 48
1 u = 48 ÷ 3 = 16
Total number of apples at first
= 10 u
= 10 x 16
= 160
Number of green apples at first
= 160 ÷ 2
= 80
Number of green apples removed at first
= 80 - 48
= 32
Total number of green apples removed
= 32 + 36
= 68
Answer(s): 68
