The number of golden apples is the same as the number of green apples in a bag. After removing
14 of the kiwis, there were 41 golden apples and 103 green apples left in the bag. Then, another 36 golden apples and 36 green apples were removed and there were
38 of the kiwis left in the end. How many golden apples were removed altogether?
| |
Golden Apples |
Green Apples |
Total |
| Before |
1 p
96 |
1 p
96 |
8 u |
| Change 1 |
- ? (14 of the total) |
- 5 u |
| After 1 |
41 |
103 |
| Change 2 |
- 36 |
- 36 |
| After 2 |
72 |
3 u |
Number of kiwis left
= 41 + 103 - 36 - 36
= 72
3 u = 72
1 u = 72 ÷ 3 = 24
Total number of kiwis at first
= 8 u
= 8 x 24
= 192
Number of golden apples at first
= 192 ÷ 2
= 96
Number of golden apples removed at first
= 96 - 41
= 55
Total number of golden apples removed
= 55 + 36
= 91
Answer(s): 91
