The number of green kiwis is the same as the number of golden apples in a bag. After removing
14 of the kiwis, there were 28 green kiwis and 116 golden apples left in the bag. Then, another 36 green kiwis and 36 golden apples were removed and there were
38 of the kiwis left in the end. How many green kiwis were removed altogether?
|
Green Kiwis |
Golden Apples |
Total |
Before |
1 p 96 |
1 p 96 |
8 u |
Change 1 |
- ? (14 of the total) |
- 5 u |
After 1 |
28 |
116 |
Change 2 |
- 36 |
- 36 |
After 2 |
72 |
3 u |
Number of kiwis left
= 28 + 116 - 36 - 36
= 72
3 u = 72
1 u = 72 ÷ 3 = 24
Total number of kiwis at first
= 8 u
= 8 x 24
= 192
Number of green kiwis at first
= 192 ÷ 2
= 96
Number of green kiwis removed at first
= 96 - 28
= 68
Total number of green kiwis removed
= 68 + 36
= 104
Answer(s): 104