The number of red apples is the same as the number of green apples in a bag. After removing
15 of the apples, there were 29 red apples and 51 green apples left in the bag. Then, another 25 red apples and 25 green apples were removed and there were
310 of the apples left in the end. How many red apples were removed altogether?
| |
Red Apples |
Green Apples |
Total |
| Before |
1 p
50 |
1 p
50 |
10 u |
| Change 1 |
- ? (15 of the total) |
- 7 u |
| After 1 |
29 |
51 |
| Change 2 |
- 25 |
- 25 |
| After 2 |
30 |
3 u |
Number of apples left
= 29 + 51 - 25 - 25
= 30
3 u = 30
1 u = 30 ÷ 3 = 10
Total number of apples at first
= 10 u
= 10 x 10
= 100
Number of red apples at first
= 100 ÷ 2
= 50
Number of red apples removed at first
= 50 - 29
= 21
Total number of red apples removed
= 21 + 25
= 46
Answer(s): 46
