The number of red grapes is the same as the number of green grapes in a bag. After removing
38 of the grapes, there were 44 red grapes and 131 green grapes left in the bag. Then, another 35 red grapes and 35 green grapes were removed and there were
38 of the grapes left in the end. How many red grapes were removed altogether?
| |
Red Grapes |
Green Grapes |
Total |
| Before |
1 p
140 |
1 p
140 |
8 u |
| Change 1 |
- ? (38 of the total) |
- 5 u |
| After 1 |
44 |
131 |
| Change 2 |
- 35 |
- 35 |
| After 2 |
105 |
3 u |
Number of grapes left
= 44 + 131 - 35 - 35
= 105
3 u = 105
1 u = 105 ÷ 3 = 35
Total number of grapes at first
= 8 u
= 8 x 35
= 280
Number of red grapes at first
= 280 ÷ 2
= 140
Number of red grapes removed at first
= 140 - 44
= 96
Total number of red grapes removed
= 96 + 35
= 131
Answer(s): 131
