The number of green grapes is the same as the number of red grapes in a bag. After removing
18 of the grapes, there were 42 green grapes and 112 red grapes left in the bag. Then, another 44 green grapes and 44 red grapes were removed and there were
38 of the grapes left in the end. How many green grapes were removed altogether?
|
Green Grapes |
Red Grapes |
Total |
Before |
1 p 88 |
1 p 88 |
8 u |
Change 1 |
- ? (18 of the total) |
- 5 u |
After 1 |
42 |
112 |
Change 2 |
- 44 |
- 44 |
After 2 |
66 |
3 u |
Number of grapes left
= 42 + 112 - 44 - 44
= 66
3 u = 66
1 u = 66 ÷ 3 = 22
Total number of grapes at first
= 8 u
= 8 x 22
= 176
Number of green grapes at first
= 176 ÷ 2
= 88
Number of green grapes removed at first
= 88 - 42
= 46
Total number of green grapes removed
= 46 + 44
= 90
Answer(s): 90