The number of green grapes is the same as the number of red grapes in a bag. After removing
14 of the grapes, there were 24 green grapes and 102 red grapes left in the bag. Then, another 28 green grapes and 28 red grapes were removed and there were
512 of the grapes left in the end. How many green grapes were removed altogether?
|
Green Grapes |
Red Grapes |
Total |
Before |
1 p 84 |
1 p 84 |
12 u |
Change 1 |
- ? (14 of the total) |
- 7 u |
After 1 |
24 |
102 |
Change 2 |
- 28 |
- 28 |
After 2 |
70 |
5 u |
Number of grapes left
= 24 + 102 - 28 - 28
= 70
5 u = 70
1 u = 70 ÷ 5 = 14
Total number of grapes at first
= 12 u
= 12 x 14
= 168
Number of green grapes at first
= 168 ÷ 2
= 84
Number of green grapes removed at first
= 84 - 24
= 60
Total number of green grapes removed
= 60 + 28
= 88
Answer(s): 88