The number of green kiwis is the same as the number of golden apples in a bag. After removing
14 of the kiwis, there were 34 green kiwis and 86 golden apples left in the bag. Then, another 36 green kiwis and 36 golden apples were removed and there were
310 of the kiwis left in the end. How many green kiwis were removed altogether?
| |
Green Kiwis |
Golden Apples |
Total |
| Before |
1 p
80 |
1 p
80 |
10 u |
| Change 1 |
- ? (14 of the total) |
- 7 u |
| After 1 |
34 |
86 |
| Change 2 |
- 36 |
- 36 |
| After 2 |
48 |
3 u |
Number of kiwis left
= 34 + 86 - 36 - 36
= 48
3 u = 48
1 u = 48 ÷ 3 = 16
Total number of kiwis at first
= 10 u
= 10 x 16
= 160
Number of green kiwis at first
= 160 ÷ 2
= 80
Number of green kiwis removed at first
= 80 - 34
= 46
Total number of green kiwis removed
= 46 + 36
= 82
Answer(s): 82
