The number of golden apples is the same as the number of green apples in a bag. After removing
14 of the kiwis, there were 32 golden apples and 160 green apples left in the bag. Then, another 48 golden apples and 48 green apples were removed and there were
38 of the kiwis left in the end. How many golden apples were removed altogether?
| |
Golden Apples |
Green Apples |
Total |
| Before |
1 p
128 |
1 p
128 |
8 u |
| Change 1 |
- ? (14 of the total) |
- 5 u |
| After 1 |
32 |
160 |
| Change 2 |
- 48 |
- 48 |
| After 2 |
96 |
3 u |
Number of kiwis left
= 32 + 160 - 48 - 48
= 96
3 u = 96
1 u = 96 ÷ 3 = 32
Total number of kiwis at first
= 8 u
= 8 x 32
= 256
Number of golden apples at first
= 256 ÷ 2
= 128
Number of golden apples removed at first
= 128 - 32
= 96
Total number of golden apples removed
= 96 + 48
= 144
Answer(s): 144
