The number of green apples is the same as the number of red apples in a bag. After removing
18 of the apples, there were 49 green apples and 49 red apples left in the bag. Then, another 28 green apples and 28 red apples were removed and there were
38 of the apples left in the end. How many green apples were removed altogether?
| |
Green Apples |
Red Apples |
Total |
| Before |
1 p
56 |
1 p
56 |
8 u |
| Change 1 |
- ? (18 of the total) |
- 5 u |
| After 1 |
49 |
49 |
| Change 2 |
- 28 |
- 28 |
| After 2 |
42 |
3 u |
Number of apples left
= 49 + 49 - 28 - 28
= 42
3 u = 42
1 u = 42 ÷ 3 = 14
Total number of apples at first
= 8 u
= 8 x 14
= 112
Number of green apples at first
= 112 ÷ 2
= 56
Number of green apples removed at first
= 56 - 49
= 7
Total number of green apples removed
= 7 + 28
= 35
Answer(s): 35
