The number of red apples is the same as the number of green apples in a bag. After removing
18 of the apples, there were 29 red apples and 139 green apples left in the bag. Then, another 48 red apples and 48 green apples were removed and there were
38 of the apples left in the end. How many red apples were removed altogether?
| |
Red Apples |
Green Apples |
Total |
| Before |
1 p
96 |
1 p
96 |
8 u |
| Change 1 |
- ? (18 of the total) |
- 5 u |
| After 1 |
29 |
139 |
| Change 2 |
- 48 |
- 48 |
| After 2 |
72 |
3 u |
Number of apples left
= 29 + 139 - 48 - 48
= 72
3 u = 72
1 u = 72 ÷ 3 = 24
Total number of apples at first
= 8 u
= 8 x 24
= 192
Number of red apples at first
= 192 ÷ 2
= 96
Number of red apples removed at first
= 96 - 29
= 67
Total number of red apples removed
= 67 + 48
= 115
Answer(s): 115
