The number of green apples is the same as the number of red apples in a bag. After removing
18 of the apples, there were 31 green apples and 95 red apples left in the bag. Then, another 47 green apples and 47 red apples were removed and there were
29 of the apples left in the end. How many green apples were removed altogether?
| |
Green Apples |
Red Apples |
Total |
| Before |
1 p
72 |
1 p
72 |
9 u |
| Change 1 |
- ? (18 of the total) |
- 7 u |
| After 1 |
31 |
95 |
| Change 2 |
- 47 |
- 47 |
| After 2 |
32 |
2 u |
Number of apples left
= 31 + 95 - 47 - 47
= 32
2 u = 32
1 u = 32 ÷ 2 = 16
Total number of apples at first
= 9 u
= 9 x 16
= 144
Number of green apples at first
= 144 ÷ 2
= 72
Number of green apples removed at first
= 72 - 31
= 41
Total number of green apples removed
= 41 + 47
= 88
Answer(s): 88
