The number of green kiwis is the same as the number of golden apples in a bag. After removing
14 of the kiwis, there were 31 green kiwis and 185 golden apples left in the bag. Then, another 48 green kiwis and 48 golden apples were removed and there were
512 of the kiwis left in the end. How many green kiwis were removed altogether?
|
Green Kiwis |
Golden Apples |
Total |
Before |
1 p 144 |
1 p 144 |
12 u |
Change 1 |
- ? (14 of the total) |
- 7 u |
After 1 |
31 |
185 |
Change 2 |
- 48 |
- 48 |
After 2 |
120 |
5 u |
Number of kiwis left
= 31 + 185 - 48 - 48
= 120
5 u = 120
1 u = 120 ÷ 5 = 24
Total number of kiwis at first
= 12 u
= 12 x 24
= 288
Number of green kiwis at first
= 288 ÷ 2
= 144
Number of green kiwis removed at first
= 144 - 31
= 113
Total number of green kiwis removed
= 113 + 48
= 161
Answer(s): 161