The number of green apples is the same as the number of red apples in a bag. After removing
38 of the apples, there were 45 green apples and 115 red apples left in the bag. Then, another 32 green apples and 32 red apples were removed and there were
38 of the apples left in the end. How many green apples were removed altogether?
| |
Green Apples |
Red Apples |
Total |
| Before |
1 p
128 |
1 p
128 |
8 u |
| Change 1 |
- ? (38 of the total) |
- 5 u |
| After 1 |
45 |
115 |
| Change 2 |
- 32 |
- 32 |
| After 2 |
96 |
3 u |
Number of apples left
= 45 + 115 - 32 - 32
= 96
3 u = 96
1 u = 96 ÷ 3 = 32
Total number of apples at first
= 8 u
= 8 x 32
= 256
Number of green apples at first
= 256 ÷ 2
= 128
Number of green apples removed at first
= 128 - 45
= 83
Total number of green apples removed
= 83 + 32
= 115
Answer(s): 115
