The number of red grapes is the same as the number of green grapes in a bag. After removing
14 of the grapes, there were 26 red grapes and 190 green grapes left in the bag. Then, another 44 red grapes and 44 green grapes were removed and there were
49 of the grapes left in the end. How many red grapes were removed altogether?
| |
Red Grapes |
Green Grapes |
Total |
| Before |
1 p
144 |
1 p
144 |
9 u |
| Change 1 |
- ? (14 of the total) |
- 5 u |
| After 1 |
26 |
190 |
| Change 2 |
- 44 |
- 44 |
| After 2 |
128 |
4 u |
Number of grapes left
= 26 + 190 - 44 - 44
= 128
4 u = 128
1 u = 128 ÷ 4 = 32
Total number of grapes at first
= 9 u
= 9 x 32
= 288
Number of red grapes at first
= 288 ÷ 2
= 144
Number of red grapes removed at first
= 144 - 26
= 118
Total number of red grapes removed
= 118 + 44
= 162
Answer(s): 162
