The number of green grapes is the same as the number of red grapes in a bag. After removing
14 of the grapes, there were 32 green grapes and 112 red grapes left in the bag. Then, another 32 green grapes and 32 red grapes were removed and there were
512 of the grapes left in the end. How many green grapes were removed altogether?
|
Green Grapes |
Red Grapes |
Total |
Before |
1 p 96 |
1 p 96 |
12 u |
Change 1 |
- ? (14 of the total) |
- 7 u |
After 1 |
32 |
112 |
Change 2 |
- 32 |
- 32 |
After 2 |
80 |
5 u |
Number of grapes left
= 32 + 112 - 32 - 32
= 80
5 u = 80
1 u = 80 ÷ 5 = 16
Total number of grapes at first
= 12 u
= 12 x 16
= 192
Number of green grapes at first
= 192 ÷ 2
= 96
Number of green grapes removed at first
= 96 - 32
= 64
Total number of green grapes removed
= 64 + 32
= 96
Answer(s): 96