The number of green kiwis is the same as the number of golden apples in a bag. After removing
38 of the kiwis, there were 31 green kiwis and 59 golden apples left in the bag. Then, another 29 green kiwis and 29 golden apples were removed and there were
29 of the kiwis left in the end. How many green kiwis were removed altogether?
| |
Green Kiwis |
Golden Apples |
Total |
| Before |
1 p
72 |
1 p
72 |
9 u |
| Change 1 |
- ? (38 of the total) |
- 7 u |
| After 1 |
31 |
59 |
| Change 2 |
- 29 |
- 29 |
| After 2 |
32 |
2 u |
Number of kiwis left
= 31 + 59 - 29 - 29
= 32
2 u = 32
1 u = 32 ÷ 2 = 16
Total number of kiwis at first
= 9 u
= 9 x 16
= 144
Number of green kiwis at first
= 144 ÷ 2
= 72
Number of green kiwis removed at first
= 72 - 31
= 41
Total number of green kiwis removed
= 41 + 29
= 70
Answer(s): 70
