The number of green grapes is the same as the number of red grapes in a bag. After removing
14 of the grapes, there were 48 green grapes and 120 red grapes left in the bag. Then, another 42 green grapes and 42 red grapes were removed and there were
38 of the grapes left in the end. How many green grapes were removed altogether?
| |
Green Grapes |
Red Grapes |
Total |
| Before |
1 p
112 |
1 p
112 |
8 u |
| Change 1 |
- ? (14 of the total) |
- 5 u |
| After 1 |
48 |
120 |
| Change 2 |
- 42 |
- 42 |
| After 2 |
84 |
3 u |
Number of grapes left
= 48 + 120 - 42 - 42
= 84
3 u = 84
1 u = 84 ÷ 3 = 28
Total number of grapes at first
= 8 u
= 8 x 28
= 224
Number of green grapes at first
= 224 ÷ 2
= 112
Number of green grapes removed at first
= 112 - 48
= 64
Total number of green grapes removed
= 64 + 42
= 106
Answer(s): 106
