The number of red apples is the same as the number of green apples in a bag. After removing
25 of the apples, there were 45 red apples and 117 green apples left in the bag. Then, another 51 red apples and 51 green apples were removed and there were
29 of the apples left in the end. How many red apples were removed altogether?
|
Red Apples |
Green Apples |
Total |
Before |
1 p 135 |
1 p 135 |
9 u |
Change 1 |
- ? (25 of the total) |
- 7 u |
After 1 |
45 |
117 |
Change 2 |
- 51 |
- 51 |
After 2 |
60 |
2 u |
Number of apples left
= 45 + 117 - 51 - 51
= 60
2 u = 60
1 u = 60 ÷ 2 = 30
Total number of apples at first
= 9 u
= 9 x 30
= 270
Number of red apples at first
= 270 ÷ 2
= 135
Number of red apples removed at first
= 135 - 45
= 90
Total number of red apples removed
= 90 + 51
= 141
Answer(s): 141