The number of green kiwis is the same as the number of golden apples in a bag. After removing
15 of the kiwis, there were 34 green kiwis and 190 golden apples left in the bag. Then, another 70 green kiwis and 70 golden apples were removed and there were
310 of the kiwis left in the end. How many green kiwis were removed altogether?
|
Green Kiwis |
Golden Apples |
Total |
Before |
1 p 140 |
1 p 140 |
10 u |
Change 1 |
- ? (15 of the total) |
- 7 u |
After 1 |
34 |
190 |
Change 2 |
- 70 |
- 70 |
After 2 |
84 |
3 u |
Number of kiwis left
= 34 + 190 - 70 - 70
= 84
3 u = 84
1 u = 84 ÷ 3 = 28
Total number of kiwis at first
= 10 u
= 10 x 28
= 280
Number of green kiwis at first
= 280 ÷ 2
= 140
Number of green kiwis removed at first
= 140 - 34
= 106
Total number of green kiwis removed
= 106 + 70
= 176
Answer(s): 176