The number of red grapes is the same as the number of green grapes in a bag. After removing
14 of the grapes, there were 42 red grapes and 138 green grapes left in the bag. Then, another 40 red grapes and 40 green grapes were removed and there were
512 of the grapes left in the end. How many red grapes were removed altogether?
| |
Red Grapes |
Green Grapes |
Total |
| Before |
1 p
120 |
1 p
120 |
12 u |
| Change 1 |
- ? (14 of the total) |
- 7 u |
| After 1 |
42 |
138 |
| Change 2 |
- 40 |
- 40 |
| After 2 |
100 |
5 u |
Number of grapes left
= 42 + 138 - 40 - 40
= 100
5 u = 100
1 u = 100 ÷ 5 = 20
Total number of grapes at first
= 12 u
= 12 x 20
= 240
Number of red grapes at first
= 240 ÷ 2
= 120
Number of red grapes removed at first
= 120 - 42
= 78
Total number of red grapes removed
= 78 + 40
= 118
Answer(s): 118
