The number of red grapes is the same as the number of green grapes in a bag. After removing
14 of the grapes, there were 21 red grapes and 75 green grapes left in the bag. Then, another 24 red grapes and 24 green grapes were removed and there were
38 of the grapes left in the end. How many red grapes were removed altogether?
| |
Red Grapes |
Green Grapes |
Total |
| Before |
1 p
64 |
1 p
64 |
8 u |
| Change 1 |
- ? (14 of the total) |
- 5 u |
| After 1 |
21 |
75 |
| Change 2 |
- 24 |
- 24 |
| After 2 |
48 |
3 u |
Number of grapes left
= 21 + 75 - 24 - 24
= 48
3 u = 48
1 u = 48 ÷ 3 = 16
Total number of grapes at first
= 8 u
= 8 x 16
= 128
Number of red grapes at first
= 128 ÷ 2
= 64
Number of red grapes removed at first
= 64 - 21
= 43
Total number of red grapes removed
= 43 + 24
= 67
Answer(s): 67
