The number of green kiwis is the same as the number of golden apples in a bag. After removing
15 of the kiwis, there were 22 green kiwis and 170 golden apples left in the bag. Then, another 60 green kiwis and 60 golden apples were removed and there were
310 of the kiwis left in the end. How many green kiwis were removed altogether?
| |
Green Kiwis |
Golden Apples |
Total |
| Before |
1 p
120 |
1 p
120 |
10 u |
| Change 1 |
- ? (15 of the total) |
- 7 u |
| After 1 |
22 |
170 |
| Change 2 |
- 60 |
- 60 |
| After 2 |
72 |
3 u |
Number of kiwis left
= 22 + 170 - 60 - 60
= 72
3 u = 72
1 u = 72 ÷ 3 = 24
Total number of kiwis at first
= 10 u
= 10 x 24
= 240
Number of green kiwis at first
= 240 ÷ 2
= 120
Number of green kiwis removed at first
= 120 - 22
= 98
Total number of green kiwis removed
= 98 + 60
= 158
Answer(s): 158
