Esther, Eva, Zoe and Barbara jointly contributed to the cost of a present for their colleague. Esther's contribution is
78 of the total contribution made by the four girls. The ratio of Barbara's contribution to the total of Eva's and Zoe's contribution is 2 : 1. What is the total contribution by the four girls if Eva's contribution is
16 of Zoe's contribution and the total amount contributed by Esther and Barbara is $1449?
Esther |
Eva |
Zoe |
Barbara |
Total |
7x21 |
1x21 |
8x21 |
|
1x7
|
2x7 |
|
|
1x1 |
6x1 |
|
|
147 u |
1 u |
6 u |
14 u |
168 u |
Working backwards.
Total amount that Eva and Zoe had is the combined repeated identity.
LCM of 1 and 7 = 7
Total amount that Eva, Zoe and Barbara had is the next combined repeated identity.
LCM of 1 and 21 = 21
Total amount contributed by Esther and Barbara
= 147 u + 14 u
= 161 u
161 u = 1449
1 u = 1449 ÷ 161 = $9
Total contribution by the four girls
= 168 u
= 168 x 9
= $1512
Answer(s): $1512